We can show this by positioning one over the other and then showing the effect of the inconsistency below this.
P
~P
x
Suppose I have expressions such P -> Q and ~P & ~ Q. Since any implication could also be expressed as the disjunction ~P v Q (remember the equivalence we call material implication), we could see the first expression as breaking up ("decomposing") into two branches. The second expression has to be rewritten with one atomic formula over the other.
P -> Q
~P & ~Q
~P
~Q
/ \
~P Q (rewriting the first expression)
x
How can we use trees to test for the validity of an argument form? Let's go back to the definition of validity: in a valid pattern we cannot have true premises and a false conclusion. In an invalid argument these could exist together--they would be consistent. Let's look at two different patterns.
P -> Q, P |- Q
P -> Q
P
~ Q (negating the original conclusion)
/ \
~P Q
x
x valid
P -> Q, Q |- P
P -> Q
Q
~P
/ \
~P Q
invalid
In the top display both branches close, so we know the form is valid. In the bottom display one branch remains open, so we know the form is not valid (in fact, it represents the formal fallacy of affirming the consequent)
Every expression can be rewritten as either a conjunction with its parts lined up or as a disjunction with branches. This might take several steps.
~(P & ~(Q v (R v ~P)))
~P v (Q v ~(R v ~P)) here we're using
DeMorgan's laws
/
\
~P
Qv~(Rv~P)
/
\
Q ~(Rv~P)
~R
P
We can see all the
possibilities for decomposing a wff in this
chart:
| P & Q | P v Q | P-> Q | P<-> Q | ~(P&Q) | ~(PvQ) | ~(P->Q) | ~(P<->Q) |
| P | / \ | / \ | / \ | / \ | ~P | P | / \ |
| Q | P Q | ~P Q | P ~P | ~P ~Q | ~Q | ~Q | P ~P |
| Q ~Q | ~Q Q |
Use both reverse-method truth tables and
consistency trees to test the following argument forms for validity.
1.
P v (Q & R),
~Q
|- P v R
2. P & (Q v R), ~R
|- P & Q
3. P -> (Q & R), ~(P
v Q) |- R
4. ~P -> (Q v R), ~(P
&
Q) |- ~R
Provide
derivations for the forms that are
valid.